1. Rational Transform F(s)
F(s) =
e-2ss+1
Isolate the delay:
F(s) = e-2s ·
F(s) = e-2s ·
1s+1
2. s-plane & Poles
Pole at s = -1. The e-2s term is a pure delay.
3. Partial Fraction Expansion
e-2s · [
1s+1
]4. Time-Domain Signal f(t)
f(t) = e-(t-2) u(t-2)
Pole Type → Time-Domain Signature
| Pole Location | Term in F(s) | Time Domain f(t) |
|---|---|---|
| Real: s = -p | 1s+p |
e-pt u(t) |
| Repeated: s = -p (x2) | 1(s+p)2 |
t e-pt u(t) |
| Complex: -σ ± jω | ω(s+σ)2+ω2 |
e-σt sin(ωt) u(t) |
| (Numerator delay) | e-as | Shift right: f(t-a) |
What to notice
- The exponential term e-2s in the numerator represents a time shift, not a pole.
- First find the inverse transform of the rational part (which is e-tu(t)).
- Then shift every 't' to 't-2' to get the final delayed response.